# A flask with vinegar in it has a mass of 160 grams. a balloon with baking soda in it has a mass of 40 grams. the balloon is attached to the flask to seal the opening and the vinegar and baking soda mixes. the balloon inflates to a large volume. what will the total mass of the balloon and flask be after the balloon inflates?

Answer: Following the Law of Conservation of Mass, you simply add the mass of both substances. Thus, 160 grams + 40 grams = 200 grams. So, even if initially, they are in liquid and solid form, they would still have the same mass even if they change phases, owing to that they are in a closed space.

200 grams, because all the atoms remain in the balloon or flask.

Explanation:

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## Related Questions

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Well all I know is that a hectogram is bigger than a decigram. Hoped that helped :)

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The concentration of a dilute aspirin solution is 0.000526 m. standard solutions of this compound were used to prepare a beer\'s law plot which gives a slope of 1550.3 m-1. what is the expected absorbance value for the aspirin solution?

The expected absorbance value for the aspirin solution is 0.815

Beer Lambert's law

From the question, we are to determine the expected absorbance value for the aspirin solution

From the Beer Lambert's law formula, we have that

A = εbc

Where A is the absorbance

ε is molar absorptivity

b is the path length

and c is the concentration

The Beer's law equation conform to the equation of a straight line, where εb is the slope of the line

Then, we can rewrite the equation as

A = mc

Where m is the slope

Now, from the given information

c = 0.000526 M

and m = 1550.3 M⁻¹

Putting the parameters into the formula, we get

A = 1550.3 × 0.000526

A = 0.8154578

A ≅ 0.815

Hence, the expected absorbance value for the aspirin solution is 0.815

0.815.

Explanation:

• We should mention Beer's law:

A = ∈bC.

Where, A is the absorbance of the solution.

b is the cell length of the cuvette.

C is the concentration of the solution.

• The calibration curve is a relation between A and C has a slope of (∈b).

We have C = 0.000526 M and a slope of (∈b) = 1550.3 M⁻¹.

∴ A = ∈bC = (1550.3 M⁻¹)(0.000526 M) = 0.815.

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The answer is step-up transformer. D

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Hope this helps :)

An original sample of K-40 has a mass of 25.00 grams. After 3.9 × 109 years, 3.125 grams of the original sample remains unchanged. What is the half-life of K-40?
(1) 1.3 × 109 y (3) 3.9 × 109 y
(2) 2.6 × 109 y (4) 1.2 × 1010 y

La respuesta correcta es

Explanation:

Hello! Let's solve this!

First we have to know the mass / mass exponent without changes

The data is:

m = 25 g

mc (mass without changes) = 3.125g

25 / 3,125 = 8 =

The exponent is 3, so we divide the number of years by three.

La respuesta correcta es

(1) 1.3*10^9 years

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Think of a resource and predict What happens to the resource when competition for it increases