PHYSICS
COLLEGE

Answer:

Answer : The volume of ethyl alcohol overflow will be, 7.49 mL

Explanation :

To calculate the volume of ethyl alcohol overflow we are using formula:

where,

= volume expand = ?

= volumetric expansion coefficient =

= initial volume = 430 mL

= final temperature =

= initial temperature =

Now put all the given values in the above formula, we get:

Thus, the volume of ethyl alcohol overflow will be, 7.49 mL

Answer:

Answer:

7.3094 ml

Explanation:

Initial volume of the glass, Vo = 430 ml

Initial temperature, T1 = 6°C

final temperature, T2 = 22°C

Temperature coefficient of glass, γg = 27.6 x 10^-6 /°C

Temperature ethyl alcohol, γa = 0.00109 /°C

Use the formula of expansion of substances

Expansion in volume of glass

ΔVg = Vo x γg x ΔT

ΔVg = 430 x 27.6 x 10^-6 x 16 = 0.1898 ml

Expansion in volume of ethyl alcohol

ΔVa = Vo x γa x ΔT

ΔVa = 430 x 0.00109 x 16 = 7.4992 ml

The amount of volume over flow is

ΔV = ΔVa - ΔVg

ΔV = 7.4992 - 0.1898

ΔV = 7.3094 ml

Thus, the amount of ethyl alcohol over flow is 7.3094 ml.

HIGH SCHOOL

If you have to apply 40n of force on a crowbar to lift a rock that weights 400n, what is the actual mechanical advantage of the crowbar

The mechanical advantage is defined as the ratio between the force produced by a machine and the force applied in input:

For the crowbar of the problem, the force applied in input is 40 N, while the force produced in output is equal to the weight of the rock that is lifted, so 400 N. Therefore, the mechanical advantage is

For the crowbar of the problem, the force applied in input is 40 N, while the force produced in output is equal to the weight of the rock that is lifted, so 400 N. Therefore, the mechanical advantage is

COLLEGE

A fireman standing on a 9.1 m high ladder operates a water hose with a round nozzle of diameter 1.8 inch. The lower end of the hose (9.1 m below the nozzle) is connected to the pump outlet of diameter 3.1 inch. The gauge pressure of the water at the pump is(gauge) Plamp-P,tin 50.6 PSI 348.875 kPa (abs) pump atmCalculate the speed of the water jet emerging from the nozzle. Assume that water is an incompressible liquid of density 1000 kg/m^3 and negligible viscosity. The acceleration of gravity is 9.8 m/s^2 . Answer in units of m/s.

Answer:

The speed of the water jet emerging from the nozzle is 24.21 m/s.

Explanation:

Given that,

Height = 9.1 m

Diameter =1.8 inch

Gauge pressure = 348.875 kPa

We need to calculate the speed of the water jet emerging from the nozzle

Using Bernoulli's equation

Put the value into the formula

Hence, The speed of the water jet emerging from the nozzle is 24.21 m/s.

MIDDLE SCHOOL

Explain the difference between reflection and refraction

Answer:Difference Between Reflection and Refraction. The phenomenon of a light beam rebounding after hitting a surface is called reflection. There's another phenomenon called refraction.

Explanation:

Here, the light changes direction, or 'bends' as it passes through the boundary between these two media.

MIDDLE SCHOOL

What is a different form of a characteristic, such as brown hair, is called

It is known as a Dominant Allele.

Dominant allele its is the answer!

COLLEGE

El Sol está en promedio a 93 millones de millas de la Tierra. ¿A cuántos metros equivale esto? Expréselo usando potencias de diez.

Hola!

93 millones de millas equivalen a 1,50 x 10¹¹ metros.

Para calcular este valor, necesitamos saber la equivalencia entre millas y metros (1 milla=1609,34m), y aplicar el siguiente factor de conversión. Para expresar el resultado en potencias de 10, se debe correr la coma a la izquierda hasta obtener un valor de una sola unidad y multiplicar este valor por 10 elevado a la cantidad de espacios que la coma se tuvo que correr a la izquierda:

Saludos!

93 millones de millas equivalen a 1,50 x 10¹¹ metros.

Para calcular este valor, necesitamos saber la equivalencia entre millas y metros (1 milla=1609,34m), y aplicar el siguiente factor de conversión. Para expresar el resultado en potencias de 10, se debe correr la coma a la izquierda hasta obtener un valor de una sola unidad y multiplicar este valor por 10 elevado a la cantidad de espacios que la coma se tuvo que correr a la izquierda:

Saludos!

MIDDLE SCHOOL

Which word describes the amount of matter in

an object?

Hi there! The answer you’re looking for is Mass! Hope this helps!

Answer:

Mass

I didn't know if there were answer choices for me to help better explain. Anyway, this is the answer

MIDDLE SCHOOL

An Aluminium bar is 3.25m long and has a diameter of 25mm. If the temperature difference between the ends is 250°C, find the rate of heat transfer along the bar. (Where the Thermal conductivity for Al is 205W/m°C) is it 5.67 W, 7.74 W, or 10.5 W?

Answer

7.74 W

Explanation

The formula for getting the the rate of heat transfer is:

=

A = πr² = π×(12.5/1000)²

= 4.908×10⁻⁴m²

Rate of heat transfer =

= 7.74 W

COLLEGE

A block with mass m=1.50 kg is initially at rest on a horizontal frictionless surface at x =0 , where x is the horizontal coordinate. A horizontally directed force is then applied to the block. The force is not constant: instead, its magnitude as a function of position is described by the relationship F(x)=(α-βx 2 )i , where x is given in units of meters, α = 2.50 N , β = 1.00 N/m2 , and i is the unit vector in the x direction. a) What is the kinetic energy of the block as it passes through x=2.00 m?

b) What is the maximum speed of the block in the interval during which it moves from its initial position to x=2.00 m?

Answer:

(a) 2.33 J.

(b) 1.87 m/s.

Explanation:

(a)

The force as a function of position is given above. Since the force is a function of position, we can assume that we will use work-energy theorem.

Therefore, the kinetic energy of the block is 2.33 J.

(b) In order to find the maximum speed in this interval, we need to investigate the acceleration of the block. Since acceleration is the derivative of velocity, velocity is at its maximum when acceleration is zero.

From Newton's Second Law:

In order this to be zero:

The velocity of the block at x = 1.58 m can be found by work-energy theorem.

HIGH SCHOOL

A mass is suspended on a vertical spring. Initially, the mass is in equilibrium. Then, it is pulled downward and released. The mass then moves up and down between the "top" and the "bottom" positions. By definition, the period of such motion is the time interval it takes the mass to move:Mark all the correct statements among those provided below. a. from the top position to the bottom. b. from the equilibrium position to the bottom. c. from the bottom position to the top. d. from the equilibrium position to the bottom and then back to the equilibrium. e. from the equilibrium position to the top and then back to the equilibrium. f. from the equilibrium position to the top. g. from the top position to the bottom and then back to the top. h. from the bottom position to the top and then back to the bottom.

Answer:

d. from the equilibrium position to the bottom and then back to the equilibrium.

g. from the top position to the bottom and then back to the top.

h. from the bottom position to the top and then back to the bottom.

Explanation:

It is the case of SHM or Simple Harmonic Motion. Firstly, there is a need to understand the time interval or time period. The standard definition of time period in simple harmonic motion is

"the time period required for the system to complete its one cycle"

Now one have to consider that the system given above, the motion of mass attached to spring will follow the path of motion from equilibrium point to bottom to equilibrium point to top, then equilibrium point to the bottom and so on.

to choose right answer you must have to consider the option, in which the starting point and ending point of the mass is same. If mass starts from top, the time it will take to reach on top again, will be defined as its time period and so in the case of bottom or equilibrium as starting point. Hence, "d", "g" and "h" are right answers.