# In one year, 2 million tonnes of glass bottles and jars were thrown away in the UK. 38% of these bottles and jars were recycled. How many tonnes of the bottles and jars were recycled?

760000

Step-by-step explanation:

you need to do 38% of 2,000,000 because 38% was recycled

## Related Questions

Round 14.235 to the nearest tenth

It is 14.100 because you are rounding down so you round 2 down to 1

ILL GIVE BRAINLIEST For the data in the table, does y vary directly with x? If it does, write an equation for the direct variation.

x y

---------------------------

4 28

6 48

8 72

a.yes,y=2x
b.yes,y=5x
c.yes,y=7x
d.no, y does not vary directly with x

Option d is correct.

no , because y does not vary directly with x.

Step-by-step explanation:

Direct variation states that a relationship between any two variables in which one is a constant multiple of the other.

in other way, when one of the  variable changes then the other changes in proportion to the first.

If y is directly proportional to x i.e,

then the equation is of the form;

where k is the constant of Variation.

From the table:

Consider any values of x and y:

Let x = 4 and y = 28

then by definition of direct variation solve for k;

28 = 4k

Divide both sides by 4 we get;

k = 7

Then the equation become: y = 7x           .....[1]

Check whether the other data follows this equation or not,

x = 6 and y = 48

Substitute in equation [1];

48 = 7(6)

48 = 42 False

Also, for;

x = 8 and  y= 72

72 = 7(8)

72 = 56  False

⇒ y= 7x does not follows the data of the given table.

Therefore, y does not vary directly with x.

A certain test preparation course is designed to help students improve their scores on the MCAT exam. A mock exam is given at the beginning and end of the course to determine the effectiveness of the course. The following measurements are the net change in 6 students' scores on the exam after completing the course: 19, 15, 9, 17, 7, 16. Using these data, construct a 95% confidence interval for the average net change in a students's score after completing the course. Assume the population is approx. normal.Step 1. calculate the sample mean for the given sample data (round answer to 1 decimal place)Step 2. Calculate the sample standard deviation for the given sample data ( round answer to 1 decimal place)Step 3. Find the critical value that should be used in constructing the confidence interval. ( round answer to 3 decimal placed)Step 4. construct the 95% confidence interval (round answer to 1 decimal place)

1)

2)

3)

4) The 95% confidence interval would be given by (8.8;18.8)

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

We can calculate the sample mean and sample deviation with the following formulas:

Step 1. calculate the sample mean for the given sample data (round answer to 1 decimal place)

Step 2. Calculate the sample standard deviation for the given sample data ( round answer to 1 decimal place)

represent the sample mean for the sample

population mean (variable of interest)

s represent the sample standard deviation

n=6 represent the sample size

The confidence interval for the mean is given by the following formula:

(1)

Step 3. Find the critical value that should be used in constructing the confidence interval. ( round answer to 3 decimal places)

In order to calculate the critical value we need to find first the degrees of freedom, given by:

Since the Confidence is 0.95 or 95%, the value of and , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,5)".And we see that

Step 4. construct the 95% confidence interval (round answer to 1 decimal place)

Now we have everything in order to replace into formula (1):

So on this case the 95% confidence interval would be given by (8.8;18.8)

Please help me don’t ignore. Due today at 1:00. Just these three questions, please show your work and give me the correct answer. Like you doing the math on paper. Thank you!

Step-by-step explanation:

I would be happy to answer them but I do not see the 3 questions.

Is 0.1km greater than 10mm?

10mm" alt="0.1km=0.1\cdot1000m=100m=100\cdot1000mm=100\ 000mm > 10mm" align="absmiddle" class="latex-formula">
Yeah it is 0.1km is a 100m

The formula for the area of a triangle is A = ½ bh. Find the area of a triangle with a base of 18 feet and a height of 7 feet.

Solve the formula for h. Find the height of a triangle with an area of 28 feet2 and a base of 8 feet.

1. 63 ft²
2. h = 2A/b; h = 7 ft

Step-by-step explanation:

1. Put the values where the variables are in the formula, then do the arithmetic.

... A = (1/2)bh = (1/2)(18 ft)(7 ft) = 63 ft²

2. Divide by the coefficient of h. Substitute the given values and do the arithmetic.

... A = (1/2)bh

The coefficient of h is b/2, so we divide by that—or multiply by its inverse, 2/b.

... 2A/b = h

Substituting the given numbers, you have ...

... 2(28 ft²)/(8 ft) = h = 7 ft

The height of the triangle is 7 ft.

Step-by-step explanation

the answer is 63 feet

The sum of three consecutive integers is 54 what is the greatest of the three integers

Let, the numbers are: x, (x+1), (x+2)
Now, x+x+1+x+2= 11
3x + 3 = 54
3x = 51
x = 51/3
x = 17

So, largest number would be: (x+2) = (17+2) = 19

In short, Your Final answer would be 19

Hope this helps!

Complete the statement. Round to the nearest hundredth if necessary. 15 cm ≈ in.

5.91 in

Step-by-step explanation:

1 cm = 0.393701 in

15 cm * 0.393701 in = 5.90551 in

Round to hundredth: 5.91 in

What is the least common multiple 5,6 and 7

Hello! For the least common multiple we will have to find factors of these numbers

For example:
5 = 1, 5, 10, 15, 20, 25, 30, 35, 45, 50, 55, 60, 65, 70, 75, 80
6 = 1, 6, 12, 18, 24, 30, 36, 42, 48, 54, 60, 66, 72, 78, 84, 90
7 = 1, 7, 14, 21, 28, 35, 42, 49, 56, 63, 70, 77, 84, 91, 98

Sometimes we can keep on going forever but we can just multiply them out as well!

5 * 6 * 7 = 30 * 7 = 210

Least common multiple will be 210! :)
The Least Common Multiple is 210