# A red cart of mass 4 kg slides to the right on a frictionless track with a velocity of 4 m/s. It collides with the stationary blue cart of mass 1 kg. After the collision, the blue cart has a velocity of 8 m/s. Calculate the velocity of the red cart after the collision.

## Answers

Answer 1
Answer:

Answer:

Speed of the red cart  after collision = 2 m/s

Explanation:

Given that

Mass of red cart,m₁ = 4 kg

u₁=4 m/s

Mass of stationary blue cart ,m₂ =1 kg

u₂ = 0 m/s

After collision speed of blue cart , v₂ =8 m/s

Speed of the red cart after collision = v₁

There is no any external force on the masses that is why the linear momentum will be conserve.

Initial linear momentum = Final linear momentum

P = m v

m₁u₁+m₂u₂ = m₁v₁+m₂v₂

4 x 4 + 1 x 0 = 4 x v₁+ 1 x 8

v₁ =2 m/s

Speed of the red cart  after collision = 2 m/s

## Related Questions

You kick a soccer ball straight up into the air with a speed of 21.2 m/s. How long does it take the soccer ball to reachbits highest point?

### Answers

Gravity increased the downward speed (or decreases the upward speed) by 9.8 m/s every second.

21.2/9.8 = 2.2 seconds

2.2 for apex!!!!!!!!!!!!

Which is the correct definition of a chemical reaction? A. Substances are mixed together. B. Substances interact to form new substances. C. Things change color. D. Substances melt.

### Answers

C things change color

The staples inside a stapler are kept in place by a spring with a relaxed length of 0.116 m. if the spring constant is 46.0 n/m, how much elastic potential energy is stored in the spring when its length is 0.146 m?

### Answers

Answer:

U = 0.0207 J

Explanation:

We know that:

U =

where U is the potential energy, K the constant of the spring and x is the deformation.

so, the deformation is calcualted as:

x = 0.146m-0.116m

x = 0.03m

Finally, replacing the values of x and K, we get:

U =

U = 0.0207 J

Use Einstein’s energy equation to solve the following problem. Recall that the speed of light is 3 x 108 m/s. If a 5.0-kg stone is completely converted to energy, what is its energy equivalent in joules?

### Answers

E =mc²

= (5.0-kg)(3 x 10^8 m/s)²

= (5.0-kg) (9×10^16m²/s²)

E =4.5×10^17 J

Answer:

Its energy equivalent in Joules is

E = 4.5 × 10^17Joules

Explanation:

The Einstein energy equation is expressed as shown

E = mc² where:

m is the mass of the stone

c is the speed of light

Given:

m = 5.0kg

c = 3 x 10^8 m/s

E = 5×(3 x 10^8)²

E = 5×(9×10^16)

E = 45 × 10^16

E = 4.5 × 10^17Joules

Dew is formed when small water droplets condense on grass. In what type of environment is dew NOT likely to form?

### Answers

Areas with less moisture are least likely to get dew, also places that are dry. For example, The southwestern part of the USA has a lot of dessert.
One country that has a lot of dessert is Australia (Outback).

Answer: In order for water droplets to condense, the air must have a relative humidity of 100%. In areas that are very dry, such as a desert, there is not enough humidity to form dew.

Explanation:

Boyle's Law states that when a sample of gas is compressed at a constant temperature, the pressure P and volume V satisfy the equation PV = C, where C is a constant. Suppose that at a certain instant the volume is 400 cm3, the pressure is 160 kPa, and the pressure is increasing at a rate of 40 kPa/min. At what rate is the volume decreasing at this instant?

### Answers

Answer:

100 cm^3/min

Explanation:

PV = C

V = 400 cm^3

P = 160 kPa

dP/dt = + 40 kPa/min

According to the question

PV = C

Differentiate both sides with respect to time

P x dV/dt + V x dP/dt = 0

160 x dV/dt = - 400 x 40

dV/dt = - 100 cm^3/min

The volume decreases by the rate of 100 cm^3/min.

Consider the equation . The dimensions of the variables v, x, and t are , , and , respectively. The numerical factor 3 is dimensionless. What must be the dimensions of the variable z, such that both sides of the equation have the same dimensions?

### Answers

Answer:

Part of the question is missing but here is the equation for the function;

Consider the equation v = (1/3)zxt2. The dimensions of the variables v, x, and t are [L/T], [L], and [T] respectively.

Answer = The dimension for z = 1/T3 i.e 1/ T - raised to power 3

Explanation:

What is applied is the principle of dimensional homogenuity

From the equation V = (1/3)zxt2.

• V has  a dimension of [L/T]
• x has a dimension of [L]
• t has a dimension of [T]
• from the equation, make z the subject of the relation
• z = v/xt2 where 1/3 is treated as a constant
• Substituting into the equation for z
• z = L/T / L x T2
• the dimension for z = 1/T3 i.e 1/ T - raised to power 3

Feng and Isaac are riding on a merry-ground. Feng rides on a horse at the outer rim of the circular platform, twice as far from the center of the circular platform as Isaac, who rides on an inner horse. When the merry-go-round is rotating at a constant angular speed, what is Feng’s angular speed?

### Answers

When the merry-go-round is rotating at a constant angular speed, what is Feng’s angular speed will be same as Isaac's.

Since, both Feng and Isaac are riding on the same marry-go-round in a circular motion. The speed of the marry-go-round is constant.

Angular speed depends on the frequency of the rotation and frequency of the rotation is irrespective of the position in a circle.

Therefore, when the merry-go-round is rotating at a constant angular speed, what is Feng’s angular speed will be same as Isaac's.

To know more about angular speed,

brainly.com/question/9684874

Answer: The question is incomplete or missing details. here is the remaining part of the question ;

1. impossible to determine

2. half of Isaac’s

3. the same as Isaac’s

4. twice Isaac’s

The angular speed of feng will be the same as that of Isaac. Hence the answer is option 3

Explanation:

Since we have been told that both feng and isaac are riding on a merry go round i.e in a circular motion, irrespective of how fast one ride above the other, the angular speed will be constant since they are riding on a merry go round, as such both feng and isaac will maintain equal angular speed, hence the angular speed of feng will be the same as that of Isaac.

A train is traveling away from you at 120 km/h. it blows its whistle, and you hear a tone of 0.400 kHz. Take the speed of sound to be 340 m/s. What frequency does the whistle actually produce? A) 444 Hz. B) 439 Hz C) 364 Hz D) 361 Hz

### Answers

Answer:B)439.21 Hz

Explanation:

Given

velocity of train

frequency of train

speed of sound

frequency from Doppler effect can be calculated by