# The flavor of anise is due to anethole, a compound with the molecular forumal C10H12O. Combustion of one mole of anethole produces 5541 kJ of thermal energy. If 0.950 g of anethole is combusted in a bomb calorimeter whose heat capacity (Ccalorimeter) is 7.854 kJ/°C, what is the change in temperature of the calorimeter?

Change in temperature of calorimeter is

Explanation:

Molar mass of anethole = 148.2 g/mol

So, 0.950 g of anethole = of anethole = 0.00641 moles of anethole

1 mol of anethole releases 5541 kJ of heat upon combustion

So, 0.00641 moles of anethole release of heat or 35.52 kJ of heat

7.854 kJ of heat increases temperature of calorimeter.

So, 35.52 kJ of heat increases or temperature of calorimeter

So, change in temperature of calorimeter is

## Related Questions

How do you tell if a compound is polar or non polar

A polar molecule is when the arrangement of the atoms in molecules are unequal where one end of the molecule has a positive charge while the other end has a negative charge. Examples of a polar molecule are water, ammonia, hydrogen sulfide and sulfur dioxide. The opposite is called a nonpolar molecule. These molecules would share their electrons equally resulting to having no partial charges in the molecule. Examples of this are most of the organic compounds like benzene and hexane, carbon tetrachloride is also a nonpolar molecule. To identify, you need to look at the structure and the electronegativities of the atoms.

What two factors determine the thermal energy in a substance

The answer to that is mass and chemical

Styrene, C8H8, is one of the substances used in the production of synthetic rubber. When styrene burns in oxygen to form carbon dioxide and liquid water under standard-state conditions at 25°C, 42.15 kJ are released per gram of styrene. Find the standard enthalpy of formation of styrene at 25°C. (Given: ?H°f[CO2(g)] = –393.5 kJ/mol, ?H°f[H2O(l)] = –285.8 kJ/mol, ?H°f[H2O(g)] = –241.8 kJ/mol)

ΔH°f(C₈H₈(l)) = 98.80 kJ/mol

Explanation:

Let's consider the combustion of styrene.

C₈H₈(l) + 10 O₂(g) → 8 CO₂(g) + 4 H₂O(l)

42.15 kJ are released per gram of styrene, that is, -42.15 kJ/g. In the balanced equation there is 1 mole of C₈H₈, so the heat released per mole is:

In order to find the standard enthalpy of formation of styrene (ΔH°f(C₈H₈(l))) we will use the following expression.

ΔH°rxn = Σ np . ΔH°f(p) - Σ nr . ΔH°f(r)

where,

ni: moles of reactants and products

ΔH°rxn = 8 mol × ΔH°f(CO₂(g)) + 4 mol × ΔH°f(H₂O(l)) - 1 mol × ΔH°f(C₈H₈(l)) - 10 mol × ΔH°f(O₂(g))

1 mol × ΔH°f(C₈H₈(l)) = 8 mol × ΔH°f(CO₂(g)) + 4 mol × ΔH°f(H₂O(l)) - 10 mol × ΔH°f(O₂(g)) - ΔH°rxn

1 mol × ΔH°f(C₈H₈(l)) = 8 mol × (-393.5 kJ/mol) + 4 mol × (-285.8 kJ/mol) - 10 mol × 0 kJ/mol - (-4390 KJ)

ΔH°f(C₈H₈(l)) = 98.80 kJ/mol

Which one of the following are appropriate units for measuring volume? A. grams
B. Newtons
C. linear feet
D. cubic centimeters

D. cubic cenimeters
100 percent sure
Among the answers i believe its D i hope you are right bye

What is a disproportionation reaction?

What is a disproportionation reaction.

From the solubility curve, which salt shows the least change in solubility as the temperature increases?

Explanation:As it has Solubility 35.7

NaCl

Explanation:

1. What structural property of sodium 4-amino-1-naphthalenesulfonate makes it very soluble in water? 2. You will have to look up the structure of this compound and comment on why it is water-soluble. Simply stating that it's polar

1. Sodium 4-amino-1-naphthalenesulfonate makes it very soluble in water as it contains a hydrate salt sodium sulfate .

2. In the structure of this compound, sodium sulphate is polar in nature.

Molecular formula:

The molecular structure of sodium 4-amino-1-naphthalenesulfonate is .

The polar part of the structure sodium sulfate makes sodium 4-amino-1-naphthalenesulfonate a hydrate salt. Salt are polar and are usually soluble in water.

brainly.com/question/11951743

Answer: it contains a hydrate salt sodium sulfate NaO4S.

4-amino-1-naphthalenesulfonate is a sodium salt. Sodium sulfate is Polar.

Explanation:

The molecular structure of sodium 4-amino-1-naphthalenesulfonate is

C10H10NNaO4S

The polar part of the structure sodium sulfate NaO4S makes sodium 4-amino-1-naphthalenesulfonate a hydrate salt. Salt are polar and are usually soluble in water.

100mL of water initially at 35°C is placed inside a calorimeter. What will be the final temperature in the calorimeter if 50g of aluminum initially at 100°C is added to the water?

51.27°C

Explanation:

We are given;

• Volume of water is 100 mL

Density of water is 1 g/mL, therefore, Mass is 100 g

• Initial temperature is 35°C
• Mass of the calorimeter is 50 g
• Initial temperature of aluminium is 100°C

We are required to calculate the final temperature of the mixture;

We are going to use the following steps;

Step 1: Calculate the amount of heat absorbed by water

Quantity of heat absorbed = mcΔT

Q = mcΔT

Assuming the final temperature is X

Then, ΔT is (X-35)°C

But, specific heat capacity of water is 4.184 J/g°C

Therefore;

Q = 100 g × 4.184 J/g°C ×  (X-35)°C

= 418.4X - 14,644 Joules

Step 2: Calculate the quantity of heat released by Aluminium

Mass of aluminium is 50 g

Specific heat capacity of aluminium is 0.90 J/g°C

Assuming the final temperature is X, thus ΔT is (100 - X)°C

Thus;

Q = 50 g × 0.9 J/g°C × (100 - X)

= 4500 - 45X Joules

Step 3: Calculate the final temperature, X°C

We need to know that the Quantity of heat absorbed is equal to the quantity of heat released.

Therefore;

418.4X - 14,644 J =  4500 - 45X J

373.4X = 19,144

X = 51.27°C

Therefore, the final temperature of the mixture is 51.27°C

When you see an image of a solid the particles of the solid are usually packed ____ but in fact there may be some ____ between them.