PHYSICS HIGH SCHOOL

The small increase in global oil production coupled with an increased demand for those resources leads to _______.

Answers

Answer 1
Answer: The correct answer for this question is this one: "b. increased prices." The small increase in global oil production coupled with an increased demand for those resources leads to increase in prices.

Here are the following choices.
a. lack of modern energy sources
b. increased prices
c. decreased competition
d. decreased prices
Answer 2
Answer:

Answer:

b. increased prices

for edgenunity

Explanation:


Related Questions

COLLEGE

In a study to determine the percentage of college students who read the newspaper, which of the following is the best sample? Every 20th student who walks by the student center

The first 50 students who arrive at a movie

The freshman at a particular school

The students in a computer class

Answers

Answer:

Every 20th student who walks by the student center is the correct answer.

Explanation:

Option B is not correct, unless the newspaper contains relevant information about the movies; however, it is possible to get this information from other sources.

C is also incorrect because the freshman at a particular school are juts a percentage of the total population and a limited group.

Letter D is also incorrect because people in a computer class don't necessarily read the paper.

However, option A is the correct answer since it is a controlled environment and it can easily be analyzed.


Every 20th student who walks by the student center

because it is random and systemized
MIDDLE SCHOOL

How can one object affect the motion of another without touching it? Give a specific example.

Answers

There are two types of forces

1. Physical force : in this type of forces we require direct contact between two bodies

2. Field force: here we do not requires any type of physical contact with the body

so here in this type of field force we do not required any contact but only due to field present near it the body can move

so here several examples are there

a) when a magnet is placed near a piece of iron then it will move towards the iron

b) a positively charged particle when come near another charged particle then it will get attracted or repelled.

so as per all above discussion we can say that an object can move without any direct contact

MIDDLE SCHOOL

a bike can climb the inclined road at uniform speed of 72 km/hr by applying force 500N what will be the power applied by the bike ?​

Answers

Answer:

10 kW

Explanation:

First convert km/hr to m/s.

72 km/hr × (1000 m / km) × (1 hr / 3600 s) = 20 m/s

The power is:

P = Fv

P = (500 N) (20 m/s)

P = 10000 W

P = 10 kW

The power applied by the bike is 10 kW.

HIGH SCHOOL

A 95.1-kg person stands on a scale in an elevator. What is the apparent weight when the elevator is (a) accelerating upward with an acceleration of 2.48 m/s2, (b) moving upward at a constant speed, and (c) accelerating downward with an acceleration of 1.84 m/s2

Answers

Answer:

Explanation:

Mass of the person in elevator

M = 95.1kg

a. When the elevator is accelerating upward at 2.48m/s²

Fnet = ma

R — W = ma

R — mg = ma

R = ma+mg

R = m(a+g)

R = 95.1(2.48+9.81)

R = 95.1 × 12.2

R = 1168.78N

b. Elevator moving upward at a constant speed

This means that it is not accelerating. Therefore, the acceleration is zero

Fnet = ma

a = 0

Fnet = 0

R - W = 0

R = W

R = mg

R = 95.1 × 9.81

R = 932.931 N.

c. Elevator accelerating downward at 1.84m/s².

Fnet = ma

Since it is downward, a is moving in -ve direction of y axis

R — W = -ma

R = W—ma

R = mg —ma

R = m(g-a)

R = 95.1(9.81—1.84)

R = 95.1 × 7.97

R = 757.947 N.

Answer:

(a) 1168.78 N, (b) 932.93 N and (c) 757.95 N, approximately.

Explanation:

In general, let's suppose the elevator is moving upward with a constant acceleration , then by applying Newton's second law on the person and writing for the normal force (which is the one the scale displays), we have

(a)

.

(b)

.

(c)

.

COLLEGE

Classical conditioning requires _____.

Answers

I would say A classical conditioning definitely demands a pairing of two stimuli
hope i helped 

Answer:

the pairing of two stimuli

Explanation:

HIGH SCHOOL

Mr. Stephenson drives his car from Dallas to Town X, a distance of 437 km. The trip takes 7.27 hours. What is the average speed of this trip in meters per second (m/s)? A. 16.7 m/s

B. 8.35 m/s

C. 60.1 m/s

D. 19.7 m/s

Answers

Average speed = (distance covered) / (time to cover the distance).

Distance covered = 437 km = 437,000 meters

Time to cover the distance = (7.27 hrs) x (3600 sec/hr) = 26,172 seconds

Average speed = (437,000 meters) / (26,172 seconds)

Average speed = 16.7 m/s

COLLEGE

If the temperature is held constant during this process and the final pressure is 683 torrtorr , what is the volume of the bulb that was originally filled with gas?

Answers

Answer:

Explanation:

Let the volume of the unknown bulb = X L

The volume of the system , after opening valve = (X + 0.72 L )

Use Boyles law gas equation,

P1V1 = P2V2 ( at temperature is constant )

Given:

P1 = 1.2 atm

P2 = 683 torr

Converting mmHg to atm,

1 atm = 760 mmHg(torr)

683 mmHg = 683/760

= 0.8987 atm

1.2X = 0.8987*(X + 0.720)

1.2X = 0.8987X + 0.6471

0.3013X = 0.6471

X = 2.15 L

MIDDLE SCHOOL

Which unit is equivalent to j/s

Answers

To be honest, there's no sure way to answer that, because you haven't defined your terms and we can't be sure of what j or s might be.

Tell you what I'll do:. I'll assume definitions for j and s, and then I'll answer the question that I invented.

Assume that j stands for Joule, the unit of energy. And assume that s stands for 'second', the unit of time.

Then j/s is the rate of transferring energy or doing work.

Its unit is the Watt, equivalent to 1 Joule per second.

In your system of notation, it would be 'w' .

Answer:

Watts

Explanation:

HIGH SCHOOL

How would the acceleration of a chain of three shopping carts compare with the acceleration of a single cart if the same force acted on both? A. 1/3 as much the single
B. 1/2 as much the single
C. 3 times as much the single
D. 2 times as much the single

Answers

So in order to know the correct answer, let us analyze the problem. Given that a = F/m where a is acceleration, F is force and m is mass, here is the solution.

a = F/m 

a' = F/3m 

a'/a = 1/3

Based on this, the correct answer would be option A. 

1/3 as much the single  Hope this helps.
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