PHYSICS
MIDDLE SCHOOL

Answer:

The distance from the crest to the equilibrium of a wave called Amplitude. The correct option is A.

What is amplitude?The maximum distance of the wave from the equilibrium position is known as the amplitude.

The distance from the equilibrium to the crest or trough of the wave is equal to the Amplitude.

Thus, the distance from the crest to the equilibrium of a wave called Amplitude. The correct option is A.

Learn more about amplitude.

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Answer:

Your answer is A. Amplitude

MIDDLE SCHOOL

15. What is the change in momentum of a car weighing 1500 kg when its speed increases from 36 km hr to 72 km/hr uniformly?

Answer:

GIVEN,

MASS, m = 1500 kg

INITIAL VELOCITY,u = 36 km/h = 36*5/18 = 10 m/s

FINAL VELOCITY ,v = 72 km/h = 72*5/18= 20 m/s

FORMULA :

CHANGE IN MOMENTUM,p = mv - mu

1500*20 - 1500*10

30000 - 15000

= 15000 kg m/s

Explanation:

HIGH SCHOOL

One person raises a 100 lb. box 5 ft. to load on a truck. Another person loads a similar box in half the time. Which statements are correct? Both men did equal work.

The first person did more work.

The second person did more work.

The second person worked faster.

Both men did equal work and the second person worked faster

HIGH SCHOOL

Match the terms Term Definition

Chromosphere A) Layer of the sun where energy is transferred by thermal conduction.

Photosphere B) Contains the sun's outer shell from which light energy is radiated.

Radiative zone C) Layer of the sun that is known for its red color and can only be seen during eclipses

Corona D) The plasma that surrounds the sun

Explanation :

(1) Chromosphere: It is a layer above the photosphere. The temperature in chromosphere increases from to . This layer is known for its red color and can only be seen during eclipses.

(2) Photosphere: It is the outer layer of the star which contains sun's outer shell from which light energy is radiated.

(3) Radiative zone: it is a layer of sun where energy is transmitted towards via radiative diffusion or conduction.

(4) Corona: It is a plasma that surrounds the sun and the other stars.

Hence, this is the required definitions.

Answer:bdca

Explanation:

HIGH SCHOOL

A thin spherical shell rolls down an incline without slipping. If the linear acceleration of the center of mass of the shell is 0.23g, what is the angle the incline makes with the horizontal?

Fnet = ma = m*0.23g = mgsinΘ - Ff

where Ff is the friction force upslope.

net torque τ = Ff * r,

but also τ = I*α =(2/3)mr² * a/r = 2mra/3 = 2mr(0.23g)/3 = 0.46mrg/3

Then Ff * r = 0.46mrg / 3

Ff = 0.46mg/3 → put this into net force equation:

m*0.23g = mgsinΘ - 0.46mg/3 → mg cancels; multiply through by 3

0.69 = 3sinΘ - 0.46

3sinΘ = 1.15

sinΘ = 1.15/3

Θ = arctan(1.15/3) = 22.54 º

HIGH SCHOOL

15 POINTS!!! WILL MARK BRAINLIEST IF CORRECT!! Newton’s first law of motion tells us that an object will move _________ unless acted on by an unbalanced force.

A) in a circle

B) in a straight line

C) with constant acceleration

D) with deceleration until it comes to a stop

Answer:

B) in a straight line

Explanation:

- According to the newton first law that states that the objects at rest will remain the same until and unless they are set in motion by some other object or any other external force acting on them that can change its motion.

- Thus do not move without the creation of an unbalanced force, the object will move in the same direction with the same speed and thus will flow in the same line.

B) it is going straight nothing is acting on it

COLLEGE

It takes 5.06 J of work to stretch a Hooke’s-law spring 13.3 cm from its unstressed length. How much the extra work is required to stretch it an additional 13.4 cm? Answer in units of J.It takes 5.06 J of work to stretch a Hooke’s-law spring 13.3 cm from its unstressed length. How much the extra work is required to stretch it an additional 13.4 cm? Answer in units of J.

Answers:

extra work required = 0.038 J

Explanation:

let X = 13.3 cm and Y = 13.4 cm, W1 be the work done to stretch the spring 13.3 cm and W2 be the work done to stretch the spring 13.4cm .let F be the force stretching the spring.

from Work and Energy principles:

W1 = F×X×cos(Ф) = F×X , since the force is acting in the direction at which the spring is stretching , cos(Ф) = 1

then :

W1 = F×X

F = W1/X

= 5.06/(13.3×10^-2)

= 38.05 J

and,

W2 = F×Y×cos(Ф) = F×Y , ince the force is acting in the direction at which the spring is stretching , cos(Ф) = 1

W2 = F×Y

= (38.5)×(13.4×10^*2)

= 5.098 J

therefore, the extra required is 5.098 - 5.06 = 0.038 J.

HIGH SCHOOL

What is the mass of cement block that requires a force of 200 n to accelerate it at 5 m/s2

F=ma

200=m5

m=40kilo grams

200=m5

m=40kilo grams

40m/s.................

HIGH SCHOOL

(a)What is the wavelength (in nanometers) of light having the frequency of 8.6x10^13 Hz?. (b) What is the frequency (in Hz) of light having a wavelength of 566nm?

The speed of the wave is:

a) If we are considering a light ray, speed is "c". The wavelenght will be:

b) The frequency will be:

a) If we are considering a light ray, speed is "c". The wavelenght will be:

b) The frequency will be:

HIGH SCHOOL

Which of the following describes one of the main features of wave-particle duality? a. as speed increases, the wave nature matter becomes more evident

b. as momentum decreases, the particle nature of the matter becomes more evident

c. as energy increases, the wave nature of matter becomes easier to observe

d. as mass increases, the wave nature of matter is less easy to observe.

Answer: as mass increases, the wave nature of matter is less easy to observe.

At the beginning of the 20th century the French physicist Louis De Broglie proposed the existence of matter waves, that is to say that all matter has a wave associated with it.

In this sense, the de Broglie wavelength is given by the following formula:

(1)

Where:

is the Planck constant

is the momentum of the atom, which is given by:

(2)

Where:

is the mass

is the velocity

Substituting (2) in (1):

is inversely proportional to ).

Therefore, if the wavelength decreases the wave nature of matter is less easy to observe.

The other options are incorrect because:

a) as increases decreases and the particle nature matter becomes more evident

b) as decreases increases and the wave nature matter becomes more evident

c) There is also a relation between the wavelength and the energy :

So, as energy increases, the particle nature matter becomes more evident and the wave nature of matter becomes harder to observe