______ properties are involved when ice melts to form water and that water boils to form steam.


Answer 1
Answer: Chemical change...................................

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Friction factor for fluid flow in pipe does not depend upon the A. pipe length. B. pipe roughness. C. fluid density & viscosity. D. mass flow rate of fluid.



C. fluid density & viscosity


In 1850, Darcy-Weisbach experimentally deduced an equation to calculate shear losses ("friction"), in a tube with permanent flow and constant diameter:

hf = (f x L x V^2) / (D x 2g)


hf: shear losses

f:  shear loss factor (pipe roughness)

g: gravity acceleration

D: tube diameter

L: tube length  

V: fluid average speed in the tube

To calculate the loss factor “f” in the Poiseuille laminar region, he proposed in 1846 the following equation:

f = 64 / Re


Re: Reynolds number

The influence of the parameters on f is quantitatively different according to the characteristics of the current.

In any straight pipeline that transports a liquid at a certain temperature, there is a critical speed below which the regimen is laminar. This critical value that marks the transition between the two regimes, laminar and turbulent, corresponds to a Re = 2300, although in practice, between 2000 and 4000 the situation is quite inaccurate. Thus:



What is the [H+] of a solution with a pH of 5.6


The concentration of the hydrogen dissociated into the solution gives the pH. When the solution has a pH of 5.6 then, the concentration of H⁺ is 2.51 × 10⁻⁶.

What is pH?

The estimation of the acidic and alkalinity of the solution based on the amount of the dissociated hydrogen or the hydronium ions in the solution gives the pH.

It is measured with the help of the pH scale that indicates the range of the acids and bases along with neutral. The formula of the pH includes the negative logarithm of the hydrogen ion concentration. pH is calculated as,

pH = - log [H⁺]


pH = 5.6

Substituting values above the concentration are calculated as,

pH = - log [H⁺]

5.6 = -log [H⁺]

[H⁺] = 10⁻⁵°⁶ ≈ 0.0000025

= 2.51 × 10⁻⁶

Therefore, the hydrogen concentration in solution with pH 5.6 is equivalent to 2.51 × 10⁻⁶.

Learn more about pH here:



Hi there!

The answer to this question is 2.5118X10^-6


The formula to solve this is 10^-pH


How many liters of a 3.67 M K2SO4 solution are needed to provide 57.3 g of K2SO4(molar mass 174.01 g/mol)? Recall that M is equivalent to mol/L.


Answer: Amount of volume needed in Litres is 0.09L


Given that the concentration in Mol/L =3.67M

Mass of K2SO4 = 57.3g

Molar mass of K2SO4 = 174.01g/mol

From stochiometry,

Mole = Mass/Molar mass

Mole = 57.3/174.01= 0.33mol.

Concentration in mol/L=



Volume= 0.33/3.67

Volume = 0.09L

Therefore the volume of K2SO4 needed is 0.09L


Using the example reaction aA + bB → cC + dD write the potential first order and second order rate laws


Given the equation aA + bB → cC + dD, which is an irreversible reaction, the most common rate laws are the product of the concentration of the reactants, each raised to a power.

This is the the general form of such laws.

r = K [A]^m * [B]^n

The order of the reaction is the sum of the exponents: m + n.

For first order reaction m+ n = 1, yields to the next potential laws:

m = 1, n = 0 => r = k [A]
m = 0, n = 1 => r = k [B]
m=0.5, n = 0.5 => r = [A]^0.5 [B]^0.5

And other combinations where the sum of the exponents are 1.

For second order reactions, m + n = 2, these are some potential laws:

m = 1, n = 1 => r = k[A][B]
m=0, n = 2 => r = k[B]^2
m=2, n = 0 => r = k[A]^2

m=1.5, n = 0.5 => r = k[A]^1.5 [B]^0.5

As you see there are many potential laws all of them with the form

r = [A]^m [B]^n, being the order of the reaction m + n

What are the numbers used in the binary code? Group of answer choices
0, 1, 2
1, 2
0, 1
0, 1, 2, 3, 4


The study of coding is called computer language. There are different types of computer language and these are Java, C++, etc

The correct answer is option C that is 0,1

What is a binary number?
  • A binary number is a number expressed in the base-2 numeral system or binary numeral system, a method of mathematical expression that uses only two symbols: typically "0" and "1".
  • The base-2 numeral system is a positional notation with a radix of 2. Each digit is referred to as it, or binary digit.

According to the question, the correct answer is 0 and 1 as all the codes are made from the sequence of these numbers.

Hence, the correct answer is option C.

For more information about the coding, refer to the link:-

The correct answer is 1s and 0s.


What happens to the total amount of matter and energy during a chemical reaction ?


It would be conserved

Which of these chemical formulas — Cl2 , KCI, Ar, NO2– represents both an element and a molecule ?


The answer is: Cl2.

Chlorine is diatomic molecule made of two chlorine atoms.

Diatomic molecules are molecules made of two atoms.

They can be homonuclear (molecule made of two atoms of the same element) and heteronuclear (molecule made of two different atoms).

Chlorine (Cl) is halogen element.

Halogen elements are in group 17: fluorine (F), chlorine (Cl), bromine (Br) and iodine (I). They are very reactive and easily form many compounds.

The answer is Cl2. Hope this helps!


What would the volume (L) of 6.6 g of CO2 be if it were measured at the same temperature and pressure as that of the experiment (only 2 decimal places are needed)? Enter only the number of liters; do NOT include the "L" for liters.



The correct answer is 3.36 L


The molecular weight of CO₂ is 44 g/mol (2 O + 1 C= (2 x (16 g/mol )) + 12 g/mol). We have 44 g in 1 mol CO₂, and we want to know how many mol are in 6.6 g:

44 g -------------- 1 mol CO₂

6.6 g -------------- X= 6.6 g x 1 mol / 44 g = 0.15 mol

In normal conditions of temperature and pressure, 1 mol of ideal gas occupies 22.4 L of volume, thus:

1 mol CO₂ ------------ 22.4 L

0.15 mol -------------- X= 3.36 L

So, 6.6 g CO₂ are equivalent to 0.15 mol CO₂ and they occupy 3.36 L.


How are molecules and compounds related??

Someone please help me with this one


Molecules make up compounds
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