# **99 POINTS** I WILL GIVE BRAINLIEST ANSWER! EXPLAIN ANSWER! A squirrel sees a BIG acorn being thrown from a tree by a chipmunk and attempts to snatch it. The acorn is thrown from a 10.0 m high branch and with a horizontal velocity of 1.1 m/s. The squirrel on the ground is 5.0 m from the base of the tree. What is the of the squirrel’s average velocity if it grabs the acorn in its mouth just as it touches the ground?

Answer: Since the acorn is thrown horizontally, the initial vertical velocity is 0 m/s. Let’s use the following equation to determine the time to fall 10 meters.

d = vi * t + ½ * a * t^2, vi = 0, a = 9.8
10 = 4.9 * t^2
t = √(10/4.9)
This is approximately 1.43 seconds. Let’s use the following equation to determine the horizontal distance it moves.

d = v * t = 1.1 * √(10/4.9)
This is approximately 1.57 meters. To determine the horizontal distance between the acorn and squirrel, subtract this distance from 5 meters.

d = 5 – 1.1 * √(10/4.9)

This is approximately 3.83 meters. To catch the acorn, the squirrel must move this distance in the same time as the acorn falls 10 meters.

Average velocity = ([5 – 1.1 * √(10/4.9] ÷ √(10/4.9) = 2.4 m/s

I hope this helps you to understand how to solve this type of problem.

Hello!

For big answers like this I write it down on a piece of paper but I don't know how to put it into my answer :/

The average velocity of the squirrel is 2.4 m/s.

I hope it helps!

## Related Questions

What does it mean to say mass and weight are preportional to each other?

It means that if the mass of a mass is increased by some factor, and nothing else changes, then the weight of that mass increases by exactly the same factor.

consider the following scenario: you live near the shoreline and hear a report that an earthquake hit the ocean floor near your location. your town may experience

Tsunamis because earthquakes caused in or near water and the energy creates massive waves

The transfer of heat by a moving liquid or gas is called conduction true or false?

False its really its not true

You are 80 kg and you want to push over a player that is 100 kg with a force of 1200 N at 20 degrees above the horizontal. You both have a static friction coefficient of 0.95. If he is pushing back with 1200 N at 20 degrees below horizontal on you, will you accelerate backwards?

Explanation:

Whenever we want to discuss the motion of a body,we need to consider the forces acting on that body and not the force it is exerting on other bodies.

Let be the force exerted by the other player on you.

Horizontal force exerted by other player is where is the angle between the direction of force and horizontal.

Given,

So,the horizontal force is

Vertical force exerted is

Normal reaction force from ground is the sum of vertical force and my weight=

Let the coefficient of static friction be

given,

Maximum frictional force is

Since the maximum frictional force is greater than the horizontal force,I will not accelerate backwards.

A ride-sharing car moving along a straight section of road starts from rest, accelerating at 2.00 m/s2 until it reaches a speed of 38.0 m/s. Then the vehicle moves for 85.0 s at constant speed until the brakes are applied, stopping the vehicle in a uniform manner in an additional 5.00 s. (a) How long is the ride-sharing car in motion (in s)?
(b) What is the average velocity of the ride-sharing car for the motion described? (Enter the magnitude in m/s.)

case 1

initial speed of the car= 0 m/s

acceleration = 2 m/s²

final speed = 38 m/s

time taken to reach at the speed of 38 m/s

using equation of motion

v = u + at

38 = 0 + 2t₁

t₁ = 19 s

time for which car is moving with constant speed t₂ = 85 s

time taken to stop the vehicle t₃ = 5 s

a) Total ride time

t = t₁ + t₂ + t₃

t = 19 + 85 + 5

t = 109 s

b) distance travel in case 1

using equation of motion

v² = u² + 2 a s

38² = 2 x 2 x s₁

s₁ = 361 m

when car is moving with constant velocity

s₂ = v t

s₂ = 38 x 85

s₂ = 3230 m

when car is to stop

using equation of motion to calculate the deceleration of the car

v = u + at

0 = 38 + a x 5

a = -7.6 m/s²

distance traveled

v² = u² + 2 a s

0² = 38² - 2 x 7.6 s₃

s₃ = 95 m

total distance

s = s₁ + s₂ + s₃

s = 361 + 3230 + 95

s = 3686 m

Light can be described as a wave or as a particle known as a photon. The speed of light c is 3.00 ✕ 108 m/s. (a) Sirius is the brightest star in the night sky, 8.18 ✕ 1016 m from the Earth. Find the time it takes a photon to reach us from Sirius. Give your answer in years. (Assume one year is 365 days.)

The answer is 8.64 light years.

Explanation:

The formula used for this is the light travel equations.

where d = distance light travels in one year

c  = speed of light

t = seconds in one year

now

Now we have calculated the distance light covers in one year and we have distance from Sirius star to earth which is given in the statement

Dividing the distance of sirius from earth to the distance light travels in one year will give the time required for light to reach earth from Sirius .

Therefore, it will take 8.64 light years for a photon to reach us from Sirius.

Scientists are testing a new drug, which they think might allow people to memorize large amounts of information. Group A is taking a sugar pill. Group B is taking the new drug. Both groups are 25–35 years old and are not taking any other medicine. After a month, both groups will be given a memorization test, and scientists will compare each group’s ability to memorize new information. Which choice is the independent (manipulated) variable? A.
the sugar pill

B.
the new drug

C.
the ability to retain short-term memories

D.
the test subjects

C I think is the answer

A ball, which has a mass of 1.25 kg, is thrown straight up from the top of a building 225 meters tall with a velocity of 52.0 m/s. what will be the momentum of this ball just as it reaches the ground

First we will find the speed of the ball just before it will hit the floor

so in order to find the speed of the cart we will first use energy conservation

So by solving above equation we will have

now in order to find the momentum we can use

When compared to strong nuclear force , gravitational force is

Weaker; it is related to mass

Gravitational force is very weaker;