PHYSICS HIGH SCHOOL

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A squirrel sees a BIG acorn being thrown from a tree by a chipmunk and attempts to snatch it. The acorn is thrown from a 10.0 m high branch and with a horizontal velocity of 1.1 m/s. The squirrel on the ground is 5.0 m from the base of the tree. What is the of the squirrel’s average velocity if it grabs the acorn in its mouth just as it touches the ground?

Answers

Answer 1
Answer: Since the acorn is thrown horizontally, the initial vertical velocity is 0 m/s. Let’s use the following equation to determine the time to fall 10 meters. 

d = vi * t + ½ * a * t^2, vi = 0, a = 9.8 
10 = 4.9 * t^2 
t = √(10/4.9) 
This is approximately 1.43 seconds. Let’s use the following equation to determine the horizontal distance it moves. 

d = v * t = 1.1 * √(10/4.9) 
This is approximately 1.57 meters. To determine the horizontal distance between the acorn and squirrel, subtract this distance from 5 meters. 

d = 5 – 1.1 * √(10/4.9) 

This is approximately 3.83 meters. To catch the acorn, the squirrel must move this distance in the same time as the acorn falls 10 meters. 

Average velocity = ([5 – 1.1 * √(10/4.9] ÷ √(10/4.9) = 2.4 m/s 

I hope this helps you to understand how to solve this type of problem.
Answer 2
Answer:

Hello!

For big answers like this I write it down on a piece of paper but I don't know how to put it into my answer :/

The average velocity of the squirrel is 2.4 m/s.

I hope it helps!


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What does it mean to say mass and weight are preportional to each other?

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It means that if the mass of a mass is increased by some factor, and nothing else changes, then the weight of that mass increases by exactly the same factor.

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consider the following scenario: you live near the shoreline and hear a report that an earthquake hit the ocean floor near your location. your town may experience

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Tsunamis because earthquakes caused in or near water and the energy creates massive waves
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The transfer of heat by a moving liquid or gas is called conduction true or false?

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You are 80 kg and you want to push over a player that is 100 kg with a force of 1200 N at 20 degrees above the horizontal. You both have a static friction coefficient of 0.95. If he is pushing back with 1200 N at 20 degrees below horizontal on you, will you accelerate backwards?

Answers

Answer:I will not accelerate backwards.

Explanation:

Whenever we want to discuss the motion of a body,we need to consider the forces acting on that body and not the force it is exerting on other bodies.

Let be the force exerted by the other player on you.

Horizontal force exerted by other player is where is the angle between the direction of force and horizontal.

Given,

So,the horizontal force is

Vertical force exerted is

Normal reaction force from ground is the sum of vertical force and my weight=

Let the coefficient of static friction be

given,

Maximum frictional force is

Since the maximum frictional force is greater than the horizontal force,I will not accelerate backwards.

COLLEGE

A ride-sharing car moving along a straight section of road starts from rest, accelerating at 2.00 m/s2 until it reaches a speed of 38.0 m/s. Then the vehicle moves for 85.0 s at constant speed until the brakes are applied, stopping the vehicle in a uniform manner in an additional 5.00 s. (a) How long is the ride-sharing car in motion (in s)?
(b) What is the average velocity of the ride-sharing car for the motion described? (Enter the magnitude in m/s.)

Answers

Answer

case 1

initial speed of the car= 0 m/s

acceleration = 2 m/s²

final speed = 38 m/s

time taken to reach at the speed of 38 m/s

using equation of motion

v = u + at

38 = 0 + 2t₁

t₁ = 19 s

time for which car is moving with constant speed t₂ = 85 s

time taken to stop the vehicle t₃ = 5 s

a) Total ride time

    t = t₁ + t₂ + t₃

    t = 19 + 85 + 5

   t = 109 s

b) distance travel in case 1

  using equation of motion

   v² = u² + 2 a s

   38² = 2 x 2 x s₁

    s₁ = 361 m

  when car is moving with constant velocity

    s₂ = v t

    s₂ = 38 x 85

    s₂ = 3230 m

 when car is to stop

  using equation of motion to calculate the deceleration of the car

  v = u + at

  0 = 38 + a x 5

      a = -7.6 m/s²

  distance traveled

   v² = u² + 2 a s

   0² = 38² - 2 x 7.6 s₃

    s₃ = 95 m

total distance

    s = s₁ + s₂ + s₃

    s = 361 + 3230 + 95

    s = 3686 m

COLLEGE

Light can be described as a wave or as a particle known as a photon. The speed of light c is 3.00 ✕ 108 m/s. (a) Sirius is the brightest star in the night sky, 8.18 ✕ 1016 m from the Earth. Find the time it takes a photon to reach us from Sirius. Give your answer in years. (Assume one year is 365 days.)

Answers

Answer:

The answer is 8.64 light years.

Explanation:

The formula used for this is the light travel equations.

where d = distance light travels in one year

c  = speed of light

t = seconds in one year

now

Now we have calculated the distance light covers in one year and we have distance from Sirius star to earth which is given in the statement

Dividing the distance of sirius from earth to the distance light travels in one year will give the time required for light to reach earth from Sirius .

Therefore, it will take 8.64 light years for a photon to reach us from Sirius.

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B.
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C.
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D.
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