# What is the frequency of infrared light of 1.0 x 10-4 m wavelength?

The frequency of infrared light will be 3×10¹². Frequency is defined as the number of cycles occurring in a unit second.

What is the frequency?

Frequency is defined as the number of repetitions of a wave occurring waves in 1 second.

The given data in the problem is;

f is the frequency of infrared light=?

is the wavelength= 1.0 x 10-4 m

v is the speed of light = 3×10⁸ m/sewc

Frequency is given by the formula as;

Hence the frequency of infrared light will be 3×10¹².

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Answer: Speed of light= wavelenght * frequency

Frequency = (3x10^8)/(1 x 10^-4)
= 3 x 10^+12

## Related Questions

PLEASE HELP!!!! What is the frequency of a wave if the wave speed is 24 m/s and the wavelength is 2 m? Enter your answer in the space provided

Frequency = (wave speed) / (wavelength)

Frequency = (24 m/s)  /  (2 m)

Frequency = 12 per second .

Where is that space to put the answer into ?

If there is gravity on earth than why don't the birds and clouds fall down? ​

Birds don't fall down when they fly because their wings build lift when they flap them. Clouds don't fall down because the water particles that they keep are spread out for miles, so gravity has little effect on them.

For the same reason that you're able to walk up the stairs when you feel like it.  A force is used that works in the direction opposite to gravity and exceeds it.

Radio waves can be used to transmit information. What is an advantage of this method in computer technology? A) Computers can run faster. B) Computers can be wireless. C) Computers can store more data. D) Computers can be made smaller.

If you use radio waves to transmit and receive information, then you don't need to connect cables to all the devices that read or write the information. Computers and telephones can be made WIRELESS. This is a big help when you're riding in the car or the school bus, and your phone rings or you want to check your email !

b

Explanation:

An amateur player is about to throw a dart with an initial velocity of 15 meters/second onto a dartboard that is at a distance of 2.7 meters. Calculate the vertical distance by which the player will miss the target if he throws the dart horizontally, in line with the dartboard.A. 0.08 meters
B.
0.16 meters
C.
0.32 meters
D.
1.8 meters

vertical distance, s = 0.16 meters

Explanation:

It is given that,

An amateur player is about to throw a dart with an initial velocity of 15 meters/second onto a dartboard.

Dashboard is placed at a distance of 2.7 meters.

Calculating time from velocity and distance i.e.

Using second equation of motion for finding vertical distance :

Here, u = 0 (for vertical velocity )

s = 0.162 meters

or s = 0.16 meters

Hence, the vertical distance by which the player will miss the target if he throws the dart horizontally, in line with the dartboard is 0.16 meters.

A 0.74-g sample of a compound is burned in a bomb calorimeter, producing a temperature change from 23.02 oC to 27.65 oC. The heat capacity of the calorimeter is determined to be 4.78 kJ/oC. What is ΔE (aka ΔU, in kJ/g) for the combustion of this compound? Enter your answer as an integer.

It will be 29.90 KJ/gram

Explanation:

We have given mass of compound burn m = 0.74 gram

Temperature is changes from

So change in temperature

Heat capacity is given as

We know that is given as

In KJ/gram it will be

When the acceleration of a mass on a spring is zero, the velocity is at a .

When the velocity of a mass on a spring is zero, the acceleration is at a
.

1) Maximum

2) Maximum

Explanation:

The force acting on a mass on a spring is given by Hooke's law; in magnitude:

where

F is the force

k is the spring constant

x is the displacement

Also we know from Newton's second law that we can write

where

m is the mass

a is the acceleration

So we can write the equation as

(1)

From this relationship, we see that the acceleration is directly proportional to the displacement.

On the other hand, we know that the total mechanical energy of the system mass-spring is constant, and it is given by

(2)

where the first term is the elastic potential energy while the second term is the kinetic energy, and where

v is the velocity of the mass

From eq. (2), it is clear that when displacement increases, velocity decreases, and vice-versa; however, from eq.(1) we also know that acceleration is proportional to the displacement.

Therefore this means that:

- When acceleration increases, velocity decreases

- When acceleration decreases, velocity increases

Therefore, the two answers here are:

- When the acceleration of a mass on a spring is zero, the velocity is at a  maximum

When the velocity of a mass on a spring is zero, the acceleration is at a  maximum

A charge q produces an electric field of strength 4E at a distance of d away. Determine the electric field strength at a distance of d away. a.) E

b.) E

c.) 36E

d.) 9E

c.) 36E

Explanation:

The magnitude of the electric field is given by the expression

(1)

where k is the Coulomb's constant, q is the charge that generates the field, and d is the distance from the charge.

In this problem, we have that the magnitude of the field at a distance d is 4E, so we can rewrite the previous equation as

Now we want to determine the electric field at a distance of away. Substituting into (1), we find

(2)

We also know that

(3)

So combining (2) with (3), we find a relationship between the original field and the new field:

36E

Explanation:

Light passes through a diffraction grating with a slit spacing of 0.001 mm. A viewing screen is 100 cm behind the grating. If the light is blue, with a wavelength of 450 nm, at about what distance from the center of the interference pattern will the first-order maximum appear? A. 5 cm
B. 25 cm
C. 50 cm
D. 100 cm

Explanation:

Given

Slit spacing

viewing screen is at a distance of

wavelength of light

Condition for diffraction maxima is

for first order maxima m=1

i.e.

Distance of first order maxima from center is

A piece of plastic has a net charge of +2.00 ?c. how many more protons than electrons does this piece of plastic have? (e = 1.60 × 10-19 c)