MATHEMATICS
MIDDLE SCHOOL

Answer: You will save $2.69 from that 3 books

MIDDLE SCHOOL

The sum of the page numbers on the facing pages of a book is 761. What are the page numbers?

Answer:

761 *2+1 is the formula

MIDDLE SCHOOL

PLEASE HELP!!! 20 POINTS!!! Which of the following is equivalent to the statement below?

If 3x + 1 = 10, then x ≠ 2.

Select the best answer from the choices provided.

A. If x ≠ 2, then 3x + 1 = 10.

B. If 3x + 1 = 10, then x = 2.

C. If x = 2, then 3x + 1 = 10.

D. If x = 2, then 3x + 1 ≠ 10.

Answer: Choice DIf x = 2, then 3x+1 does not equal 10.

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Arguments in the form "if this, then that" are known as conditionals. The original conditional can be written in the form "If P, then Q". The P and Q are placeholders for statements. In this case, replace P with "3x+1 = 10" and replace Q with "x does not equal 2"

It turns out that the contrapositive is entirely identical to the original conditional. The contrapositive is in the form "If not Q, then not P". You swap P and Q, also you add "not"s to each to negate them both.

"P" means "3x+1 = 10", so "not P" means "3x+1 does not equal 10"

"Q" means "x does not equal 2", so "not Q" means "x = 2"

"If P, then Q" ----> "if 3x+1 = 10, then x does not equal 2"

"If not Q, then not P" ----> "if x = 2, then 3x+1 does not equal 10" is the proper contrapositive we want.

Answer:

jygeidycge9d7cge9

Step-by-step explanation:

because im albert einstein

MIDDLE SCHOOL

Bob gets paid more in tips when he works more hours at the restaurant. Which is the dependent variable? A. hours worked B. tips paid

A. hour worked. . . . . .. .. .. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . ..

Obviously it's A. hour worked i hope this help:) have a nice day

MIDDLE SCHOOL

What is the value of 3 in 136,422

Ten thousandths place value (30,000)

HIGH SCHOOL

Hey, can someone please teach me this? I haven't been at school to learn it and I have a quiz later. Example:

The scores on the SAT form a normal distribution with a mean of 500 and a standard deviation of 100.

What is the minimum score necessary to be in the top 15% of the SAT scores?

Find the range of values that define the middle 80% of the distribution of SAT scores.

Answer:

604

Step-by-step explanation:

"Top 15%" corresponds to the rightmost area under the standard normal curve to the right of the mean. That means 85% of the area under this curve will be to the left. Which z-score corresponds to the area 0.85 to the left?

Using a calculator (invNorm), find this z-score: invNorm(0.85) = 1.0346.

Which raw score corresponds to this z-score?

Recall the formula for the z-score:

x - mean

z = ------------------

std. dev.

Here we have:

x - 500

z = ------------------ - 1.0364, or x - 500 = 103.64. Then the minimum score

100 necessary to be in the top 15% of the scores is

found by adding 500 to both sides:

x = 603.64

MIDDLE SCHOOL

WHich is shorter 3/4 of a minute or 2/4 of an hour

3/4 of a minute is 45 seconds,

whereas 2/4 or 1/2 of an hour

would equal 30 minutes

3/4 of a minute I shorter by far

MIDDLE SCHOOL

68 goes into 481 how many. times in rounding

The best thing to do is to use a calculator and divided 481 by 68.

481/68= 7.0375

Therefore, rounded, it is 7, with 5 remaining

Hope this helps :)

481/68= 7.0375

Therefore, rounded, it is 7, with 5 remaining

Hope this helps :)

68 goes into 481 7 times in rounding because the 0 makes the seven stay the same

MIDDLE SCHOOL

Factorize:

81x^4 - ya^4

Let's simplify step-by-step.

81x4−ya4

81x4+−a4y

Answer:

−a4y+81x4

You can’t factorize that...?

HIGH SCHOOL

Find the following product ^5 square root 4x^2* ^5 square root 4x^2?

Given expression: .

We need to find the product of above given expression.

We can see that both radical expressions being multiplied are of 5th root.

So, we could multiply inside expressions of the 5th root in both radicals.

.

Therefore,

.

We can't simplify 5th root of 16 and 5th root of x^4.

Therefore, final answer isAnswer:

B!!!!!

Step-by-step explanation:

I just took the test on edg 2020