PHYSICS
HIGH SCHOOL

Answer:

The Mack truck has the higher force of impact, Mini cooper has the greater impulse, greater change in momentum occurs in Mini cooper, and the Mack truck has greater deceleration.

A characteristic of a moving body that it possesses due to its mass and motion and is equal to the sum of its mass and speed. Momentum is a vector quantity, which means it has magnitude with direction.

Due to its size and higher center of gravity, the Mack truck would impact with a larger force. Since a tiny cooper is lighter and smaller than a Mack truck, it would have a higher impulse. Due to its lesser weight and the fact that the Mack truck's impact would exert more force on it, the mini cooper would also experience a bigger change in momentum.

Due to its greater weight and longer slow down time, the Mack truck would experience a greater deceleration.

To know more about momentum:

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Answer: The Mack truck would have the greater force of impact due to its size and higher center of gravity. The mini cooper would have the greater impulse because it is much smaller and lighter than a Mack truck. The mini cooper would also have a greater change in momentum because it is lighter and the impact from the Mack truck would cause a stronger force into the mini cooper.

The mack truck would have the greater deceleration because it is much heavier and it would take a lot more time to slow down.

The mack truck would have the greater deceleration because it is much heavier and it would take a lot more time to slow down.

MIDDLE SCHOOL

as a roller coaster car starts down a slope, it’s velocity is 4m/s. But 3 seconds later it’s velocity is 22m/s in the same direction. What is its acceleration

Formula for acceleration= v2-v1/time

so 22-4/3 is 6m/s^2

so 22-4/3 is 6m/s^2

COLLEGE

A raft is made of a plastic block with a density of 650 kg/m 3 , and its dimensions are 2.00 m Ã 3.00 m Ã 5.00 m. 1. what is the volume of the raft? _________________________________________________________________ 2. what is its mass? _________________________________________________________________ 3. what is its weight? _________________________________________________________________ 4. what is the raft's ap parent weight in water? (hint: density of water = 1.00 Ã 10 3 kg/m 3 ) _________________________________________________________________ 5. what is the buoyant force on the raft in water? _________________________________________________________________ 6. what is the mass of the displaced water? _________________________________________________________________ 7. what is the volume of the displaced water? _________________________________________________________________ 8. how much of the raft's volume is below water? how much is above? _________________________________________________________________ 9. answer items 5 â 8 using ethanol (density = 0.806 Ã 10 3 kg/m 3 ) instead of water.

1) The volume of the raft is the product between the lenghts of its three dimensions:

2) The mass of the raft is the product between its density, d, and its volume, V:

3) The weight of the raft is the product between its mass m and the gravitational acceleration, :

4) The apparent weight is equal to the difference between the weight of the raft and the buoyancy (the weight of the displaced fluid):

where is the water density and is the volume of displaced fluid.

The density of the raft () is smaller than the water density (), this means that initially the buoyancy (which has upward direction) is larger than the weight (downward direction) and so the raft is pushed upward, until it reaches a condition of equilibrium and it floats. At equilibrium, the weight and the buoyancy are equal and opposite in sign:

and therefore, the apparent weight will be zero:

5) The buoyant force B is the weight of the displaced fluid, as said in step 4):

When the raft is completely immersed in the water, the volume of fluid displaced is equal to the volume of the raft, . Therefore the buoyancy in this situation is

However, as we said in point 4), the raft is pushed upward until it reaches equilibrium and it floats. At equilibrium, the buoyancy will be equal to the weight of the raft (because the raft is in equilibrium), so:

6) At equilibrium, the mass of the displaced water is equal to the mass of the object. In fact, at equilibrium we have W=B, and this can be rewritten as

where is the mass of the displaced water. From the previous equation, we obtain that .

7) Since we know that the mass of displaced water is equal to the mass of the raft, using the relationship we can rewrite as:

and so

8) The volume of water displaced is (point 7) . This volume is now "filled" with part of the volume of the raft, therefore is also the volume of the raft below the water level. We can calculate the fraction of raft's volume below water level, with respect to the total volume of the raft, :

Viceversa, the volume of raft above the water level is . Therefore, the fraction of volume of the raft above water level is

9) Let's repeat steps 5-8 replacing , the water density, with , the ethanol density.

9-5) The buoyant force is given by:

when the raft is completely submerged. Then it goes upward until it reaches equilibrium and it floats: in this condition, B=W, so the buoyancy is equal to the weight of the raft.

9-6) Similarly as in point 6), the mass of the displaced ethanol is equal to the mass of the raft:

9-7) Using the relationship , we can find the volume of displaced ethanol:

9-8) The volume of raft below the ethanol level is equal to the volume of ethanol displaced: . Therefore, the fraction of raft's volume below the ethanol level is

Consequently, the raft's volume above the ethanol level is

and the fraction of volume above the ethanol level is

2) The mass of the raft is the product between its density, d, and its volume, V:

3) The weight of the raft is the product between its mass m and the gravitational acceleration, :

4) The apparent weight is equal to the difference between the weight of the raft and the buoyancy (the weight of the displaced fluid):

where is the water density and is the volume of displaced fluid.

The density of the raft () is smaller than the water density (), this means that initially the buoyancy (which has upward direction) is larger than the weight (downward direction) and so the raft is pushed upward, until it reaches a condition of equilibrium and it floats. At equilibrium, the weight and the buoyancy are equal and opposite in sign:

and therefore, the apparent weight will be zero:

5) The buoyant force B is the weight of the displaced fluid, as said in step 4):

When the raft is completely immersed in the water, the volume of fluid displaced is equal to the volume of the raft, . Therefore the buoyancy in this situation is

However, as we said in point 4), the raft is pushed upward until it reaches equilibrium and it floats. At equilibrium, the buoyancy will be equal to the weight of the raft (because the raft is in equilibrium), so:

6) At equilibrium, the mass of the displaced water is equal to the mass of the object. In fact, at equilibrium we have W=B, and this can be rewritten as

where is the mass of the displaced water. From the previous equation, we obtain that .

7) Since we know that the mass of displaced water is equal to the mass of the raft, using the relationship we can rewrite as:

and so

8) The volume of water displaced is (point 7) . This volume is now "filled" with part of the volume of the raft, therefore is also the volume of the raft below the water level. We can calculate the fraction of raft's volume below water level, with respect to the total volume of the raft, :

Viceversa, the volume of raft above the water level is . Therefore, the fraction of volume of the raft above water level is

9) Let's repeat steps 5-8 replacing , the water density, with , the ethanol density.

9-5) The buoyant force is given by:

when the raft is completely submerged. Then it goes upward until it reaches equilibrium and it floats: in this condition, B=W, so the buoyancy is equal to the weight of the raft.

9-6) Similarly as in point 6), the mass of the displaced ethanol is equal to the mass of the raft:

9-7) Using the relationship , we can find the volume of displaced ethanol:

9-8) The volume of raft below the ethanol level is equal to the volume of ethanol displaced: . Therefore, the fraction of raft's volume below the ethanol level is

Consequently, the raft's volume above the ethanol level is

and the fraction of volume above the ethanol level is

HIGH SCHOOL

Why do waves move faster at higher temperatures and in a solid phase?

Higher temperatures means more energy, and a solid phase means the particles are close together. This results in highly energized particles that bump into the particles close to them, who in turn bump into more particles.

Answer: D- There is more energy and the particles are closer together.

Explanation:

Did it on edg. Hope this helps!!

MIDDLE SCHOOL

A canoe started its trip at 8 am. If the cannoe travelled at a speed of 70 mph how far did it travel by 1:36 pm?

The canoe traveled 392 miles.

COLLEGE

A man pulls a sled at a constant velocity across a horizontal snow surface. if a force of 80 n is being applied to the sled rope at an angle of 53Â° to the ground, what is the force of friction between sled and snow?

A constant velocity implies the two forces must be equal and opposite.

Friction acts horizontal to the ground, therefore we must find the force applied to the sled rope that acts horizontal to the ground.

Do this by resolving:

Force = 80cos53

The force opposing this is equal, and so also = 80cos53 = 48 N (2 sig. fig.)

Friction acts horizontal to the ground, therefore we must find the force applied to the sled rope that acts horizontal to the ground.

Do this by resolving:

Force = 80cos53

The force opposing this is equal, and so also = 80cos53 = 48 N (2 sig. fig.)

Answer:

The force of friction between sled and snow is 48.14 N

Explanation:

It is given that,

Force applied on the sled, F = 80 N

The angle with the sled and the ground is 53 degrees. We need to find the force of friction between sled and snow.

The horizontal force acting in the horizontal direction is given by :

So, the force of friction between sled and snow is 48.14 N. Hence, this is the required solution.

HIGH SCHOOL

How do changes in light wavelengths support the idea that the universe is expanding? A. Light from other galaxies shifts toward the blue end of the spectrum, which shows that the galaxies are moving away from Earth.

B. Light from other galaxies shifts toward the red end of the spectrum, which shows that the galaxies are moving away from Earth.

C. Light from other galaxies shifts toward the red end of the spectrum, which shows that the galaxies are moving toward Earth.

D. Light from other galaxies shifts toward the blue end of the spectrum, which shows that the galaxies are moving toward Earth.

Answer:

B. Light from other galaxies shifts toward the red end of the spectrum, which shows that the galaxies are moving away from Earth.

Explanation:

As per Doppler's Effect wavelength and frequency of a wave will change with respect to an observer depending on observer's movement. If the observer moves closer, the spectrum will shift towards blue end and if it moves away, the spectrum will shift towards the red end.

When Spectrums of distant galaxies were observed we saw that the spectrum shifts towards the red end. This indicated towards the movement of galaxies away from Earth. This is also known as Red shifting. This also proves the Big Bang theory and that universe is expanding.

As per the Doppler's Effect

B. Light from other galaxies shifts toward the red end of the spectrum, which shows that the galaxies are moving away from Eart

B. Light from other galaxies shifts toward the red end of the spectrum, which shows that the galaxies are moving away from Eart

HIGH SCHOOL

Both retinal disparity and convergence increase as an object gets closer to the individual.

That statement is true

Retinal disparity : space between your eyes that allow binocular vision to create depth perception

Retinal Convergence : Space between your eyes that signal visual moves to the retina

They both will increases as an object get closer to the individual, allowing them acknowledge and observe the existence of the object

Retinal disparity : space between your eyes that allow binocular vision to create depth perception

Retinal Convergence : Space between your eyes that signal visual moves to the retina

They both will increases as an object get closer to the individual, allowing them acknowledge and observe the existence of the object

Answer:

true

Explanation:

MIDDLE SCHOOL

Human resource professionals are reviewing the needs of a company that is building a new factory. The company needs people who can weld electronic

elements together, test them, and package them securely. The HR

professionals conclude that four kinds of workers could complete this

process. Their work is the HR function of

O

A. recruitment

O

B. job design

O

C. employee retention

O

D. selection

Their work is the HR function of "recruitment".

Answer: Option A

Explanation:

The complete procedure that involves of filtering on candidates profile, taking, selectivity and nominating appropriate applicants for positions within an organization, either permanently or on temporary basis is called as "Recruitment". Recruitment team also comes under the department of human resources.

The recruiter's pay scale is set by the management, and their job role falls within the department of human resources. Although the recruitment team functions independently, the human resource department often designates them as employees.

MIDDLE SCHOOL

Sam is getting ready to go to bat in his first major league baseball game. He wants to lower his stress level just before batting. He becomes extremely relaxed by practicing deep breathing in the on-deck circle before stepping up to the plate. What might you expect his performance to be?

he will be good and surprise