MATHEMATICS
HIGH SCHOOL

Answer:

The distance between points C(-1,4) and D(2,0) is 5 units.

What is distance formula?The distance between two points of the xy-plane can be found using the distance formula. The distance formula is:

√[(x₂ - x₁)² + (y₂ - y₁)²].

Now given coordinates of two points are,

Point C has the coordinates (–1, 4)

Point D has the coordinates (2, 0)

Therefore we have,

x₁ = -1

y₁ = 4

x₂ = 2

y₂ = 0

Now distance between C(-1,4) and D(2,0) = √[(x₂ - x₁)² + (y₂ - y₁)²]

= √[{(2 -(-1)}² + (0 - 4)²]

= √[(2+ 1)² + (-4)²]

= √3² + 16

= √9 + 16

= √25

= 5 units

Thus, the distance between points C(-1,4) and D(2,0) is 5 units.

To learn more about coordinates :

brainly.com/question/15192654

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Answer: Use the distance formula: sqrt[(x1-x2)^2 - (y1-y2)^2]

x1: -1

x2: 2

y1: 4

y2: 0

Answer: 5

x1: -1

x2: 2

y1: 4

y2: 0

Answer: 5

MIDDLE SCHOOL

sabine and jack know that 1 kilogram = 2.2 pounds and 1 pound = 0.454 kilogram. they each write an expression to convert 50 pounds to kilogram. is either student correct? explain how you know and find the correct answer to nearest kilogram.

Answer:

50 pounds = 22.7 kilograms

Step-by-step explanation:

Yes both are correct

Sabine :

2.2 pounds = 1 kilogram

1 pound = 1/ 2.2 kilogram = 0.454 kilogram

50 pounds = 50 * 0.454 =22.7 kilograms

HIGH SCHOOL

Stefan measured a weight of a package as 15.375 pounds. The actual weight of the package is 15.125 pounds. What is the approximate percent error Stefan made in measuring the weight of the package?write ur answer to the nearest percent.

Part b

Alexis measured the weight of the same package and got the same percent error as Stefan. Alexis and Stefan both measured different weights of the package.

What weight in pounds did Alexis measure. Explain how u know

15.375/15.125 x 100 =~98.4

The ~% is 98.4%

Error = ~2.6%

Part B

Be a near amount. Can be

The ~% is 98.4%

Error = ~2.6%

Part B

Be a near amount. Can be

MIDDLE SCHOOL

73210 the digit 3 stands

To digit 3 stands for 3000

The digit stands for 3,000.

MIDDLE SCHOOL

What is 128/56 simplified⁉️

To simplify this, try to look for the greatest common factor that both numbers have, which is in this case is 8 (you can find this by using prime factorization, which is using prime numbers to multiply to the number). Since the greatest common factor is 8, you divide the numerator and the denominator by 8 which will give you an answer of 16/7.

HIGH SCHOOL

Jack's average in math for the first nine weeks was an 88. his second nine weeks average decreased 12.5% what was his average for the second nine weeks? please explain how you got your answer.

10% of 88 = 8.8

2.5% of 88 = 2.2

2.2 + 8.8 = 11

88 - 11 = 77

Well 10% of 88= 8.8

5% then would be 4.4, so then 2.5% would be 2.2.

So it would be 10% (8.8) + 2.5% (2.2) = 10.1

So for the second nine weeks his average decreased by 12.5% (10.1) so it would be, 88-10.1= 77.9

Answer = 77.9

Hope that's correct haha

5% then would be 4.4, so then 2.5% would be 2.2.

So it would be 10% (8.8) + 2.5% (2.2) = 10.1

So for the second nine weeks his average decreased by 12.5% (10.1) so it would be, 88-10.1= 77.9

Answer = 77.9

Hope that's correct haha

MIDDLE SCHOOL

Can anyone pls solve this..is the answer 0

Answer:

0

Step-by-step explanation:

Simplify the following:

81^(1/4) - 8 216^(1/3) + 15 32^(1/5) + sqrt(225)

Hint: | Simplify radicals.

216^(1/3) = (6^3)^(1/3) = 6:

81^(1/4) - 86 + 15 32^(1/5) + sqrt(225)

Hint: | Simplify radicals.

32^(1/5) = (2^5)^(1/5) = 2:

81^(1/4) - 8×6 + 15×2 + sqrt(225)

Hint: | Simplify radicals.

81^(1/4) = (3^4)^(1/4) = 3:

3 - 8×6 + 15×2 + sqrt(225)

Hint: | Multiply -8 and 6 together.

-8×6 = -48:

3 + -48 + 15×2 + sqrt(225)

Hint: | Multiply 15 and 2 together.

15×2 = 30:

3 - 48 + 30 + sqrt(225)

Hint: | Look for the difference of two identical terms.

(-48 + 30 + sqrt(225)) + 3 = 0:

Answer: 0

MIDDLE SCHOOL

The ratio of girls to boys in a science class is 5 to 6 can there be fifteen boys explain why or why not

The ratio of girls to boys is 5:6.

Let the unknown number of girls be x.

If there are 15 boys in the same ratio, then the ratio of girls to boys is x:15.

Set the ratios equal as a proportion and solve for x.

5/6 = x/15

x = 15 * 5/6

x = 12.5

For the same ratio, you need 12.5 girls.

Since the number of girls must be a whole number,

there cannot be 15 boys.

Let the unknown number of girls be x.

If there are 15 boys in the same ratio, then the ratio of girls to boys is x:15.

Set the ratios equal as a proportion and solve for x.

5/6 = x/15

x = 15 * 5/6

x = 12.5

For the same ratio, you need 12.5 girls.

Since the number of girls must be a whole number,

there cannot be 15 boys.

HIGH SCHOOL

2,) What is the solution of the system? Use the substitution method.

y+6=4x

8x−2y=14

A) The only solution is (14, 12)

B)The only solution is (12, 14)

C)There are an infinite number of solutions.

D)There is no solution.

NO SOULUTION HOPE THIS HELPS

HIGH SCHOOL

If f(x), what is f^-1 (x)?

It is the inverse of f(x). For example if f(x) = x the inverse f^-1(x) =1/x