If a certain mass of mercury has a volume of 0.002 m3 at a temperature of 20°C, what will be the volume at 50°C? A. 0.002010812 m3
B. 0.000010812 m3
C. 0.004021624 m3
D. 0.002021624 m3


Answer 1
Answer: Note that the density of mercury is
(i) 13545 kg/m^3 at 20 deg.C
(ii) 13472 kg/m^3 at 50 deg, C

For a given mass, M kg, by using the volume at 20 deg. C, obtain
M = (13545 kg/m^3)*(0.002 m^3) = 27.09 kg .

Let V m^3 = volume at 50 deg. C
(13472 kg/m^3)*(V m^3) = 27.09 kg
V = 27.09/13472 = 0.002010837 m^3

The closest answer is A. 0.002010812 m^3

Answer 2
Answer: You answer is Option A. 0.002010812 m3 Hope this helps :)

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